代碼如下所示:
SELECT @i:=@i+1 rowNum,if(@total=t.s_score,@rank,@rank:=@i) rank,@total:=t.s_score,t.*from(select t1.* ,t2.s_score from student t1 LEFT JOIN score t2 on t1.s_id=t2.s_id and t2.c_id="01" ORDER BY t2.s_score desc)t,(select @i:=0,@rank:=0,@total:=null) s ;SELECT @i:=@i+1 rowNum,if(@total=t.s_score,@rank,@rank:=@rank+1) rank,@total:=t.s_score,t.*from(select t1.* ,t2.s_score from student t1 LEFT JOIN score t2 on t1.s_id=t2.s_id and t2.c_id="01" ORDER BY t2.s_score desc)t,(select @i:=0,@rank:=0,@total:=null) s ;
Mysql 獲取成績排序后的名次
其實(shí)就是輸出mysql的排序后的行號(hào)
RT:獲取單個(gè)用戶的成績?cè)谒杏脩舫煽冎械呐琶?/p>
可以分兩步:
1、查出所有用戶和他們的成績排名
select id,maxScore,(@rowNum:=@rowNum+1) as rowNo from t_user, (select (@rowNum :=0) ) b order by t_user.maxScore desc
2、查出某個(gè)用戶在所有用戶成績中的排名
select u.rowNo from ( select id,(@rowNum:=@rowNum+1) as rowNo from t_user, (select (@rowNum :=0) ) b order by t_user.maxScore desc ) u where u.id="2015091810371700001";
總結(jié)
以上所述是小編給大家介紹的Mysql排序獲取排名,希望對(duì)大家有所幫助,如果大家有任何疑問請(qǐng)給我留言,小編會(huì)及時(shí)回復(fù)大家的。在此也非常感謝大家對(duì)VeVb武林網(wǎng)網(wǎng)站的支持!
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