正在看的db2教程是:用shell抽取，更新db2的數(shù)據(jù)。為工作需要而寫(xiě)的shell處理db2數(shù)據(jù)庫(kù)的程序用shell抽取db2的數(shù)據(jù)，并進(jìn)行處理。
#SQL文定義
SQL="SELECT AAA, BBB, CCC FROM MYTBL1"
#執(zhí)行SQL
SDATA=`db2 "$SQL"`
#返回值判斷
if [ $? -ne 0 ]
then
#顯示db2返回的錯(cuò)誤信息
echo "$SDATA"
exit 1
fi
#對(duì)取得的數(shù)據(jù)進(jìn)行處理。
echo "$SDATA" | sed -e '4,/^$/!d;/^$/d' |
while read AAA BBB CCC
do
echo "AAA IS $AAA, BBB IS $BBB, CCC IS $CCC"
done
#取得數(shù)據(jù)件數(shù)
echo "$SDATA" | sed -n -e '/^$/{1,3d;n;s/[^0-9]*/([0-9]*/)[^0-9]*//1/;p;}' | read CNT
echo "The count of selected data is $CNT."
exit 0★更新db2的數(shù)據(jù)，并取得更新結(jié)果
SQL="UPDATE MYTBL1 SET AAA='2005',BBB='05',CCC='12'"
#執(zhí)行SQL
SDATA=`db2 -a "$SQL"`
#取得SQLCODE
echo "$SDATA" | sed -n -e 's/^.*sqlcode: /([-,0-9][0-9]*/).*//1/p' | read SQLCODE
echo "Sqlcode is $SQLCODE."
#取得SQLSTATE
echo "$SDATA" | sed -n -e 's/^.*sqlstate: /([-,0-9][0-9]*/).*//1/p' | read SQLSTATE
echo "Sqlstate is $SQLSTATE."
#取得更新件數(shù)(即sqlerrd的第三個(gè)值)
echo "$SDATA" | sed -n -e '/sqlerrd/s/^.*(3) /([-,0-9][0-9]*/).*//1/p' | read UPDCNT
echo "Updated data's count is $UPDCNT."
#取得sqlerrd的第五個(gè)值
echo "$SDATA" | sed -n -e '/sqlerrd/{n;s/^.*(5) /([-,0-9][0-9]*/).*//1/;p;}' | read SQLERRD5
echo "Sqlerrd(5) is $SQLERRD5."
