不管是哪種 Windows DIB 子類型,這種文件格式總是由 14 位文件頭和 40 位信息頭組成。這兩個標頭精確包含有關文件的存儲內容和存儲次序的信息。有關標頭中每一項的確切含義,請參考 Microsoft Software Development Kit (SDK)。文件其余部分的內容隨信息頭中數據的不同而不同。
我們看一下本文要處理的兩種子類型。24 位格式很簡單:RGB(紅-綠-藍)顏色值(3 個字節,并按 BGR 排序)緊接在信息頭之后。但是,每個掃描行都被補足到 4 個字節。按照說明文檔(請參閱 Microsoft SDK)的說法,這種“補足”是為了優化 Windows 位圖繪圖 API。同時,底部的掃描行是文件中的第一項內容 -- 因此相對普通的圖形坐標系統(其矢量方向的正向分別為向下和向右)而言,必須從后向前讀取圖像。
// 解釋數據。 int nsize = (((int)bf[5]&0xff)< < 24) (((int)bf[4]&0xff)< < 16) (((int)bf[3]&0xff)< < 8) (int)bf[2]&0xff; System.out.println("File type is :"+(char)bf[0]+(char)bf[1]); System.out.println("Size of file is :"+nsize);
int nbisize = (((int)bi[3]&0xff)< < 24) (((int)bi[2]&0xff)< < 16) (((int)bi[1]&0xff)< < 8) (int)bi[0]&0xff; System.out.println("Size of bitmapinfoheader is :"+nbisize);
int nwidth = (((int)bi[7]&0xff)< < 24) (((int)bi[6]&0xff)< < 16) (((int)bi[5]&0xff)< < 8) (int)bi[4]&0xff; System.out.println("Width is :"+nwidth);
int nheight = (((int)bi[11]&0xff)< < 24) (((int)bi[10]&0xff)< < 16) (((int)bi[9]&0xff)< < 8) (int)bi[8]&0xff; System.out.println("Height is :"+nheight);
int nplanes = (((int)bi[13]&0xff)< < 8) (int)bi[12]&0xff; System.out.println("Planes is :"+nplanes);
int nbitcount = (((int)bi[15]&0xff)< < 8) (int)bi[14]&0xff; System.out.println("BitCount is :"+nbitcount);
// 查找表明壓縮的非零值 int ncompression = (((int)bi[19])< < 24) (((int)bi[18])< < 16) (((int)bi[17])< < 8) (int)bi[16]; System.out.println("Compression is :"+ncompression);
int nsizeimage = (((int)bi[23]&0xff)< < 24) (((int)bi[22]&0xff)< < 16) (((int)bi[21]&0xff)< < 8) (int)bi[20]&0xff; System.out.println("SizeImage is :"+nsizeimage);
int nXPm = (((int)bi[27]&0xff)< < 24) (((int)bi[26]&0xff)< < 16) (((int)bi[25]&0xff)< < 8) (int)bi[24]&0xff; System.out.println("X-Pixels per meter is :"+nxpm);
int nypm = (((int)bi[31]&0xff)< < 24) (((int)bi[30]&0xff)< < 16) (((int)bi[29]&0xff)< < 8) (int)bi[28]&0xff; System.out.println("Y-Pixels per meter is :"+nypm);
int nclrused = (((int)bi[35]&0xff)< < 24) (((int)bi[34]&0xff)< < 16) (((int)bi[33]&0xff)< < 8) (int)bi[32]&0xff; System.out.println("Colors used are :"+nclrused);
int nclrimp = (((int)bi[39]&0xff)< < 24) (((int)bi[38]&0xff)< < 16) (((int)bi[37]&0xff)< < 8) (int)bi[36]&0xff; System.out.println("Colors important are :"+nclrimp);
if (nbitcount==24) { // 24 位格式不包含調色板數據,但掃描行被補足到 // 4 個字節。 int npad = (nsizeimage / nheight) - nwidth * 3; int ndata[] = new int [nheight * nwidth]; byte brgb[] = new byte [( nwidth + npad) * 3 * nheight]; fs.read (brgb, 0, (nwidth + npad) * 3 * nheight); int nindex = 0; for (int j = 0; j < nheight; j++) { for (int i = 0; i < nwidth; i++) { ndata [nwidth * (nheight - j - 1) + i] = (255&0xff)< < 24 (((int)brgb[nindex+2]&0xff)< < 16) (((int)brgb[nindex+1]&0xff)< < 8) (int)brgb[nindex]&0xff; // System.out.println("Encoded Color at (" +i+","+j+")is:"+nrgb+" (R,G,B)= (" +((int)(brgb[2]) & 0xff)+"," +((int)brgb[1]&0xff)+"," +((int)brgb[0]&0xff)+")"); nindex += 3; } nindex += npad; }
image = createImage ( new MemoryImageSource (nwidth, nheight, ndata, 0, nwidth)); } else if (nbitcount == 8) { // 必須確定顏色數。假如 clrsused 參數大于 0, // 則顏色數由它決定。假如它等于 0,則根據 // bitsperpixel 計算顏色數。 int nNumColors = 0; if (nclrused > 0) { nNumColors = nclrused; } else { nNumColors = (1&0xff)< < nbitcount; } System.out.println("The number of Colors is"+nNumColors);