原題： A data stream is a real-time, continuous, ordered sequence of items. Some examples include sensor data, Internet traffic, financial tickers, on-line auctions, and transaction logs such as Web usage logs and telephone call records. Likewise, queries over streams run continuously over a period of time and incrementally return new results as new data arrives. For example, a temperature detection system of a factory warehouse may run queries like the following. Query-1: “Every five minutes, retrieve the maximum temperature over the past five minutes.” Query-2: “Return the average temperature measured on each floor over the past 10 minutes.” We have developed a Data Stream Management System called Argus, which PRocesses the queries over the data streams. Users can register queries to the Argus. Argus will keep the queries running over the changing data and return the results to the corresponding user with the desired frequency. For the Argus, we use the following instruction to register a query: Register Q num Period Q num (0 < Q n um ≤ 3000) is query ID-number, and Period (0 < Period ≤ 3000) is the interval between two consecutive returns of the result. After Period seconds of register, the result will be returned for the first time, and after that, the result will be returned every Period seconds. Here we have several different queries registered in Argus at once. It is confirmed that all the queries have different Q num. Your task is to tell the first K queries to return the results. If two or more queries are to return the results at the same time, they will return the results one by one in the ascending order of Q num. Input The first part of the input are the register instructions to Argus, one instruction per line. You can assume the number of the instructions will not exceed 1000, and all these instructions are executed at the same time. This part is ended with a line of ‘#’. The second part is your task. This part contains only one line, which is one positive integer K (≤ 10000). Output You should output the Q num of the first K queries to return the results, one number per line. Sample Input Register 2004 200 Register 2005 300 # 5 Sample Output 2004 2005 2004 2004 2005
中文： 給你一堆命令，每一條命令分為Register Q_num Period ，表示每隔Period秒就會產生一個Q_num。現在讓你輸出前k個Q_num是多少。如果多個事件同時發生，先處理Q_num小的。
#include <bits/stdc++.h>using namespace std;struct reg{ int q,p,mark; reg(int QQ,int pp) { q=qq; p=pp; mark=p; } bool Operator > (const reg &r) const { if(this->mark!=r.mark) return this->mark>r.mark; else return this->q>r.q; }};vector<reg> vr;string s;int q,p,k;void solve(){ priority_queue<reg,vector<reg>,greater<reg>> pq(vr.begin(),vr.end()); while(k>0) { reg ans=pq.top(); pq.pop(); //cout<<ans.q<<" "<<ans.p<<" "<<ans.mark<<endl; cout<<ans.q<<endl; k--; ans.mark+=ans.p; pq.push(ans); } while(!pq.empty()) pq.pop(); vr.clear();}int main(){ ios::sync_with_stdio(false); while(cin>>s) { if(s=="#") { cin>>k; solve(); } else { cin>>q>>p; reg r(q,p); vr.push_back(r); } } return 0;}解： 訓練指南上面緊接著那道“一個簡單問題”的題目，亞洲區域賽居然有這么簡單的題目！ 很簡單，只要把這些命令按照Period從小到大建立一個堆，堆頂肯定是Period最小的，輸出結果然后彈出后，把剛剛輸出命令的時間增加一個Period，然后再放回堆中。輸出前k個即可。
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