一、一般頁面登錄超時驗證，可以用過濾器filter，如下：
package com.lg.filter;import java.io.IOException;import javax.servlet.Filter;import javax.servlet.FilterChain;import javax.servlet.FilterConfig;import javax.servlet.ServletException;import javax.servlet.ServletRequest;import javax.servlet.ServletResponse;import javax.servlet.http.HttpServletRequest;import javax.servlet.http.HttpServletResponse;import com.lg.func.MyFunc;public class LoginFilter implements Filter{public void destroy() {}public void doFilter(ServletRequest request, ServletResponse response,FilterChain chain) throws ServletException, IOException {HttpServletRequest request1=(HttpServletRequest)request;HttpServletResponse response1=(HttpServletResponse)response;chain.doFilter(request, response);//放行。讓其走到下個鏈或目標資源中String url=request1.getServletPath();System.out.println("Demo1過濾前"+url);MyFunc myFunc = new MyFunc(request1,response1);System.out.println("Demo1過濾前"+url.startsWith("/index/"));if(myFunc.checkLogin2()&&!url.startsWith("/index/")){response1.sendRedirect("/index_login.html");}System.out.println("Demo1過濾后");}public void init(FilterConfig arg0) throws ServletException {// TODO Auto-generated method stubSystem.out.println("===========init========過濾后");}}web.xml配置
<filter><filter-name>Demo1Filter</filter-name><filter-class>com.lg.filter.LoginFilter</filter-class></filter><filter-mapping><filter-name>Demo1Filter</filter-name><url-pattern>*.jsp</url-pattern></filter-mapping>
二、ajax提交
提交頁面,我的頁面提示彈出框架用的asyncBox，可以改成其他的跳轉
$.ajax({type: "post",url:"a.jsp",async:false,//同步data:{"name":"fdgh"}success:function(msg){//checkLogin2(msg)判斷是否登錄超時，超時返回false，跳到登錄頁面if(checkLogin2(msg)){var obj=eval('('+msg+')');if(obj.result.indexOf("suc")>-1){alert("成功");}else{alert("失敗");}}});//是否登錄超時，超時返回false，跳到登錄頁面function checkLogin2(msg){if(msg!=null&&msg.length>0){if(msg.indexOf("DOCTYPE")>-1){checkLogin();return false;}}return true;}function checkLogin(){if(window.top != window.self){top.asyncbox.alert('登錄超時，請重新登錄', '提示', function(action){ top.location.href='/login.jsp';}); }else{asyncbox.alert('登錄超時，請重新登錄', '提示', function(action){window.location.href='/login.jsp';}); }}后臺：
1.處理數據前
if(checkLogin())return; //檢查登錄，session過期，或者未登錄，自動跳轉public boolean checkLogin() throws IOException{boolean result = false;String html = "";NativeObject u = SessionMng.getCurrentUser(request);//檢驗是否登錄超時if (u == null){html = "<!DOCTYPE HTML PUBLIC '-//W3C//DTD HTML 4.01 Transitional//EN' 'http://www.w3.org/TR/html4/loose.dtd'>/n" +"<script type='text/javascript' src='/admin/js/jquery.min.js'></script>/n" +"<script type='text/javascript' src='/admin/js/common.js'></script>/n" + "<script type='text/javascript' src='/admin/js/dialog/asyncbox.js'></script>/n" + "<script language=javascript>checkLogin();</script>/n";response.getWriter().println(html); result = true;}return result;}
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