LEFT JOIN 關鍵字會從左表 (table_name1) 那里返回所有的行,即使在右表 (table_name2) 中沒有匹配的行。
LEFT JOIN 關鍵字語法
SELECT column_name(s)FROM table_name1LEFT JOIN table_name2 ON table_name1.column_name=table_name2.column_name
注釋:在某些數據庫中, LEFT JOIN 稱為 LEFT OUTER JOIN。
創建兩張表并插入一些數據
create table class( class_id int, class_name varchar(20), class_grade char(1));insert into class values (1,'語文','A');insert into class values (2,'數學','B');insert into class values (3,'英語','C');create table score( class_id int, stu_id varchar(20), Score int);insert into score values (1,'A001',91);insert into score values (2,'A001',95);insert into score values (1,'A002',82);insert into score values (2,'A002',87);insert into score values (3,'B003',65);
查看表中的數據
mysql> select * from class;+----------+------------+-------------+| class_id | class_name | class_grade |+----------+------------+-------------+| 1 | 語文 | A || 2 | 數學 | B || 3 | 英語 | C |+----------+------------+-------------+3 rows in set (0.00 sec)mysql> select * from score;+----------+--------+-------+| class_id | stu_id | Score |+----------+--------+-------+| 1 | A001 | 91 || 2 | A001 | 95 || 1 | A002 | 82 || 2 | A002 | 87 || 3 | B003 | 65 |+----------+--------+-------+5 rows in set (0.00 sec)mysql>
比較下面幾組查詢結果
--如果你對left join足夠熟悉的話,先不要看結果,是否可以直接說出下面查詢的結果
mysql> select * from class A left join score B on A.class_id=B.class_id;+----------+------------+-------------+----------+--------+-------+| class_id | class_name | class_grade | class_id | stu_id | Score |+----------+------------+-------------+----------+--------+-------+| 1 | 語文 | A | 1 | A001 | 91 || 2 | 數學 | B | 2 | A001 | 95 || 1 | 語文 | A | 1 | A002 | 82 || 2 | 數學 | B | 2 | A002 | 87 || 3 | 英語 | C | 3 | B003 | 65 |+----------+------------+-------------+----------+--------+-------+5 rows in set (0.00 sec)mysql> select * from class A left join score B on A.class_id=B.class_id and 1=1;+----------+------------+-------------+----------+--------+-------+| class_id | class_name | class_grade | class_id | stu_id | Score |+----------+------------+-------------+----------+--------+-------+| 1 | 語文 | A | 1 | A001 | 91 || 2 | 數學 | B | 2 | A001 | 95 || 1 | 語文 | A | 1 | A002 | 82 || 2 | 數學 | B | 2 | A002 | 87 || 3 | 英語 | C | 3 | B003 | 65 |+----------+------------+-------------+----------+--------+-------+5 rows in set (0.01 sec)mysql> select * from class A left join score B on A.class_id=B.class_id and 1=0;+----------+------------+-------------+----------+--------+-------+| class_id | class_name | class_grade | class_id | stu_id | Score |+----------+------------+-------------+----------+--------+-------+| 1 | 語文 | A | NULL | NULL | NULL || 2 | 數學 | B | NULL | NULL | NULL || 3 | 英語 | C | NULL | NULL | NULL |+----------+------------+-------------+----------+--------+-------+3 rows in set (0.00 sec)mysql> select * from class A left join score B on 1=0;+----------+------------+-------------+----------+--------+-------+| class_id | class_name | class_grade | class_id | stu_id | Score |+----------+------------+-------------+----------+--------+-------+| 1 | 語文 | A | NULL | NULL | NULL || 2 | 數學 | B | NULL | NULL | NULL || 3 | 英語 | C | NULL | NULL | NULL |+----------+------------+-------------+----------+--------+-------+3 rows in set (0.00 sec)
mysql> left join的最重要特點是:不管on后面是什么條件,都會返回左表中的所有行!
mysql> select * from class A left join score B on A.class_id=B.class_id and A.class_name='語文';+----------+------------+-------------+----------+--------+-------+| class_id | class_name | class_grade | class_id | stu_id | Score |+----------+------------+-------------+----------+--------+-------+| 1 | 語文 | A | 1 | A001 | 91 || 1 | 語文 | A | 1 | A002 | 82 || 2 | 數學 | B | NULL | NULL | NULL || 3 | 英語 | C | NULL | NULL | NULL |+----------+------------+-------------+----------+--------+-------+4 rows in set (0.00 sec)mysql> select * from class A left join score B on A.class_id=B.class_id and A.class_name='數學';+----------+------------+-------------+----------+--------+-------+| class_id | class_name | class_grade | class_id | stu_id | Score |+----------+------------+-------------+----------+--------+-------+| 2 | 數學 | B | 2 | A001 | 95 || 2 | 數學 | B | 2 | A002 | 87 || 1 | 語文 | A | NULL | NULL | NULL || 3 | 英語 | C | NULL | NULL | NULL |+----------+------------+-------------+----------+--------+-------+4 rows in set (0.00 sec)mysql> select * from class A left join score B on A.class_id=B.class_id and A.class_name='英語';+----------+------------+-------------+----------+--------+-------+| class_id | class_name | class_grade | class_id | stu_id | Score |+----------+------------+-------------+----------+--------+-------+| 3 | 英語 | C | 3 | B003 | 65 || 1 | 語文 | A | NULL | NULL | NULL || 2 | 數學 | B | NULL | NULL | NULL |+----------+------------+-------------+----------+--------+-------+3 rows in set (0.01 sec)mysql> select * from class A left join score B on A.class_id=B.class_id and A.class_name='體育';+----------+------------+-------------+----------+--------+-------+| class_id | class_name | class_grade | class_id | stu_id | Score |+----------+------------+-------------+----------+--------+-------+| 1 | 語文 | A | NULL | NULL | NULL || 2 | 數學 | B | NULL | NULL | NULL || 3 | 英語 | C | NULL | NULL | NULL |+----------+------------+-------------+----------+--------+-------+3 rows in set (0.00 sec)mysql>
如果on后面的條件是左表中的列(and leftTable.colName='***'),左表中滿足條件的行和右表中的行進行匹配(根據on leftTable.id=rightTable.id);左表中不滿足條件的行,直接輸出,其對應的右表中的列都是null。
mysql> select * from class A left join score B on A.class_id=B.class_id and B.Score=90;+----------+------------+-------------+----------+--------+-------+| class_id | class_name | class_grade | class_id | stu_id | Score |+----------+------------+-------------+----------+--------+-------+| 1 | 語文 | A | NULL | NULL | NULL || 2 | 數學 | B | NULL | NULL | NULL || 3 | 英語 | C | NULL | NULL | NULL |+----------+------------+-------------+----------+--------+-------+3 rows in set (0.01 sec)mysql> select * from class A left join score B on A.class_id=B.class_id and B.Score=65;+----------+------------+-------------+----------+--------+-------+| class_id | class_name | class_grade | class_id | stu_id | Score |+----------+------------+-------------+----------+--------+-------+| 3 | 英語 | C | 3 | B003 | 65 || 1 | 語文 | A | NULL | NULL | NULL || 2 | 數學 | B | NULL | NULL | NULL |+----------+------------+-------------+----------+--------+-------+3 rows in set (0.01 sec)mysql>
如果on后面的條件是右表中的列(and rightTable.colName='***'),首先會根據(and rightTable.colName='***')過濾掉右表中不滿足條件的行;然后,左表中的行根據(on leftTable.id=rightTable.id)和右表中滿足條件的行進行匹配。
mysql> select * from class A left join score B on A.class_id=B.class_id and A.class_name='語文' and B.Score=90;+----------+------------+-------------+----------+--------+-------+| class_id | class_name | class_grade | class_id | stu_id | Score |+----------+------------+-------------+----------+--------+-------+| 1 | 語文 | A | NULL | NULL | NULL || 2 | 數學 | B | NULL | NULL | NULL || 3 | 英語 | C | NULL | NULL | NULL |+----------+------------+-------------+----------+--------+-------+3 rows in set (0.00 sec)mysql> select * from class A left join score B on A.class_id=B.class_id and A.class_name='語文' and B.Score=91;+----------+------------+-------------+----------+--------+-------+| class_id | class_name | class_grade | class_id | stu_id | Score |+----------+------------+-------------+----------+--------+-------+| 1 | 語文 | A | 1 | A001 | 91 || 2 | 數學 | B | NULL | NULL | NULL || 3 | 英語 | C | NULL | NULL | NULL |+----------+------------+-------------+----------+--------+-------+3 rows in set (0.01 sec)mysql> select * from class A left join score B on A.class_id=B.class_id and A.class_name='體育' and B.Score=90;+----------+------------+-------------+----------+--------+-------+| class_id | class_name | class_grade | class_id | stu_id | Score |+----------+------------+-------------+----------+--------+-------+| 1 | 語文 | A | NULL | NULL | NULL || 2 | 數學 | B | NULL | NULL | NULL || 3 | 英語 | C | NULL | NULL | NULL |+----------+------------+-------------+----------+--------+-------+3 rows in set (0.00 sec)mysql> select * from class A left join score B on A.class_id=B.class_id and A.class_name='體育' and B.Score=82;+----------+------------+-------------+----------+--------+-------+| class_id | class_name | class_grade | class_id | stu_id | Score |+----------+------------+-------------+----------+--------+-------+| 1 | 語文 | A | NULL | NULL | NULL || 2 | 數學 | B | NULL | NULL | NULL || 3 | 英語 | C | NULL | NULL | NULL |+----------+------------+-------------+----------+--------+-------+3 rows in set (0.00 sec)mysql>
/**********************過濾條件在on中時**********************/
總結一下,如果 left join on leftTable.id=rightTable.id 后還有其他條件:
(1)and leftTable.colName='***',過濾左表,但是左表不滿足條件的行直接輸出,并將右表對應部分置為null
(2)and rightTable.colName='***',過濾右表,對左表沒有影響
(3)and leftTable.colName='***' and rightTable.colName='***',就是上面(1)和(2)一起發揮作用
不管on后面有哪些條件,left join都要返回左表中的所有行!
mysql> select * from class A left join score B on A.class_id=B.class_id where A.class_name='語文';+----------+------------+-------------+----------+--------+-------+| class_id | class_name | class_grade | class_id | stu_id | Score |+----------+------------+-------------+----------+--------+-------+| 1 | 語文 | A | 1 | A001 | 91 || 1 | 語文 | A | 1 | A002 | 82 |+----------+------------+-------------+----------+--------+-------+2 rows in set (0.01 sec)mysql> select * from class A left join score B on A.class_id=B.class_id where A.class_name='數學';+----------+------------+-------------+----------+--------+-------+| class_id | class_name | class_grade | class_id | stu_id | Score |+----------+------------+-------------+----------+--------+-------+| 2 | 數學 | B | 2 | A001 | 95 || 2 | 數學 | B | 2 | A002 | 87 |+----------+------------+-------------+----------+--------+-------+2 rows in set (0.00 sec)mysql> select * from class A left join score B on A.class_id=B.class_id where A.class_name='英語';+----------+------------+-------------+----------+--------+-------+| class_id | class_name | class_grade | class_id | stu_id | Score |+----------+------------+-------------+----------+--------+-------+| 3 | 英語 | C | 3 | B003 | 65 |+----------+------------+-------------+----------+--------+-------+1 row in set (0.00 sec)mysql> select * from class A left join score B on A.class_id=B.class_id where A.class_name='體育';Empty set (0.00 sec)mysql> select * from class A left join score B on A.class_id=B.class_id where B.Score=90;Empty set (0.01 sec)mysql> select * from class A left join score B on A.class_id=B.class_id where B.Score=91;+----------+------------+-------------+----------+--------+-------+| class_id | class_name | class_grade | class_id | stu_id | Score |+----------+------------+-------------+----------+--------+-------+| 1 | 語文 | A | 1 | A001 | 91 |+----------+------------+-------------+----------+--------+-------+1 row in set (0.00 sec)mysql> select * from class A left join score B on A.class_id=B.class_id where A.class_name='語文' and B.Score=90;Empty set (0.00 sec)mysql> select * from class A left join score B on A.class_id=B.class_id where A.class_name='語文' and B.Score=91;+----------+------------+-------------+----------+--------+-------+| class_id | class_name | class_grade | class_id | stu_id | Score |+----------+------------+-------------+----------+--------+-------+| 1 | 語文 | A | 1 | A001 | 91 |+----------+------------+-------------+----------+--------+-------+1 row in set (0.00 sec)mysql> select * from class A left join score B on A.class_id=B.class_id where A.class_name='體育' and B.Score=90;Empty set (0.00 sec)mysql> select * from class A left join score B on A.class_id=B.class_id where A.class_name='體育' and B.Score=91;Empty set (0.00 sec)mysql>
/**********************過濾條件在where中時**********************/
過濾條件寫在where中時,先根據where條件對表進行過濾,然后再執行left join
總結
以上所述是小編給大家介紹的sql中的left join及on、where關鍵字的區別詳解,希望對大家有所幫助,如果大家有任何疑問請給我留言,小編會及時回復大家的。在此也非常感謝大家對VeVb武林網網站的支持!
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