前兩篇文章是關于字符串分割的一些經驗,今天來談下字符的合并,更確切的說是字段數據的合并吧?,F在很多公司,尤其是工廠,上下班都要刷卡。假如有以下的數據庫表,記錄著員工上下班的刷卡記錄。但是這樣直接導出或顯示,不太好看,不夠直觀。下面實現把每個員工每天的刷卡時間橫向顯示。
插入測試數據:
1 CREATE TABLE CARD_RECORD ( 2 id_ INT IDENTITY(1,1) NOT NULL PRIMARY KEY, 3 card_id INT NOT NULL, 4 swipe_date DATETIME NOT NULL 5 ) 6 GO 7 8 INSERT INTO CARD_RECORD (card_id,swipe_date) 9 SELECT '10001','2015-06-01 08:21'10 UNION ALL11 SELECT '10002','2015-06-01 08:22'12 UNION ALL13 SELECT '10001','2015-06-01 12:00'14 UNION ALL15 SELECT '10002','2015-06-01 12:01'16 UNION ALL17 SELECT '10001','2015-06-01 13:00'18 UNION ALL19 SELECT '10002','2015-06-01 13:01'20 UNION ALL21 SELECT '10002','2015-06-01 18:05'22 UNION ALL23 SELECT '10001','2015-06-01 18:12'24 UNION ALL25 SELECT '10002','2015-06-02 08:31'26 UNION ALL27 SELECT '10001','2015-06-02 08:42'28 UNION ALL29 SELECT '10001','2015-06-02 12:10'30 UNION ALL31 SELECT '10002','2015-06-02 12:11'32 UNION ALL33 SELECT '10001','2015-06-02 13:00'34 UNION ALL35 SELECT '10002','2015-06-02 13:11'36 UNION ALL37 SELECT '10001','2015-06-02 18:05'38 UNION ALL39 SELECT '10002','2015-06-02 18:12'40 UNION ALL41 SELECT '10002','2015-06-02 19:34'42 UNION ALL43 SELECT '10001','2015-06-03 08:36'44 UNION ALL45 SELECT '10002','2015-06-03 08:40'46 UNION ALL47 SELECT '10001','2015-06-03 12:20'48 UNION ALL49 SELECT '10002','2015-06-03 12:20'50 UNION ALL51 SELECT '10001','2015-06-03 12:55'52 UNION ALL53 SELECT '10002','2015-06-03 12:56'54 UNION ALL55 SELECT '10001','2015-06-03 18:05'56 GOView Code
創建字符/字段數據合并的函數:
1 IF OBJECT_ID(N'fn_time_list') IS NOT NULL 2 BEGIN 3 DROP FUNCTION fn_time_list 4 END 5 GO 6 7 CREATE FUNCTION fn_time_list (@date DATETIME,@card_id NVARCHAR(100)) 8 RETURNS NVARCHAR(MAX) 9 AS 10 BEGIN11 DECLARE @char NVARCHAR(MAX)12 DECLARE @date2 DATE13 SET @char = ''14 SET @date = CAST(@date AS DATE)15 SET @date2 = DATEADD(DAY,1,CAST(@date AS DATE))16 17 SELECT @char = @char + CONVERT(CHAR(5),swipe_date,108) + ',' FROM CARD_RECORD 18 WHERE (swipe_date >= @date AND swipe_date < @date2) AND card_id=@card_id19 ORDER BY swipe_date ASC20 21 SET @char = CASE WHEN @char = '' THEN '' ELSE SUBSTRING(@char,1,LEN(@char)-1) END22 23 RETURN (@char)24 END25 GO
最后,把數據轉換一下,展示:
1 SELECT DISTINCT card_id,CONVERT(char(10),swipe_date,23) AS swipe_date,dbo.fn_time_list(swipe_date,card_id) AS time_list2 FROM CARD_RECORD 3 ORDER BY card_id ASC,swipe_date ASC4 GO
執行結果:
這里,還可以把豎向的刷卡時間,每個時間占一個字段,橫向顯示。不過會有刷卡次數的限制,一般來說,一天預留十次刷卡記錄應該是足夠了。
1 WITH CTE1 AS ( 2 SELECT 3 card_id 4 ,CONVERT(CHAR(10),swipe_date,23) AS swipe_date 5 ,CONVERT(CHAR(5),swipe_date,108) AS swipe_time 6 FROM CARD_RECORD 7 ) 8 9 ,CTE2 AS (10 SELECT 11 ROW_NUMBER() OVER (PARTITION BY card_id,swipe_date ORDER BY card_id ASC,swipe_date ASC,swipe_time ASC) AS row_no12 ,card_id13 ,swipe_date14 ,swipe_time15 FROM CTE116 )17 18 SELECT 19 t1.card_id20 ,t1.swipe_date21 ,t1.swipe_time AS time122 ,ISNULL(t2.swipe_time,'') AS time223 ,ISNULL(t3.swipe_time,'') AS time324 ,ISNULL(t4.swipe_time,'') AS time425 ,ISNULL(t5.swipe_time,'') AS time526 ,ISNULL(t6.swipe_time,'') AS time627 ,ISNULL(t7.swipe_time,'') AS time728 ,ISNULL(t8.swipe_time,'') AS time829 ,ISNULL(t9.swipe_time,'') AS time930 ,ISNULL(t10.swipe_time,'') AS time1031 32 FROM CTE2 AS t133 LEFT JOIN CTE2 AS t2 ON t2.card_id = t1.card_id AND t2.swipe_date = t1.swipe_date AND t2.row_no = 234 LEFT JOIN CTE2 AS t3 ON t3.card_id = t1.card_id AND t3.swipe_date = t1.swipe_date AND t3.row_no = 335 LEFT JOIN CTE2 AS t4 ON t4.card_id = t1.card_id AND t4.swipe_date = t1.swipe_date AND t4.row_no = 436 LEFT JOIN CTE2 AS t5 ON t5.card_id = t1.card_id AND t5.swipe_date = t1.swipe_date AND t5.row_no = 537 LEFT JOIN CTE2 AS t6 ON t6.card_id = t1.card_id AND t6.swipe_date = t1.swipe_date AND t6.row_no = 638 LEFT JOIN CTE2 AS t7 ON t7.card_id = t1.card_id AND t7.swipe_date = t1.swipe_date AND t7.row_no = 739 LEFT JOIN CTE2 AS t8 ON t8.card_id = t1.card_id AND t8.swipe_date = t1.swipe_date AND t8.row_no = 840 LEFT JOIN CTE2 AS t9 ON t9.card_id = t1.card_id AND t9.swipe_date = t1.swipe_date AND t9.row_no = 941 LEFT JOIN CTE2 AS t10 ON t10.card_id = t1.card_id AND t10.swipe_date = t1.swipe_date AND t10.row_no = 1042 43 WHERE t1.row_no = 144 ORDER BY t1.card_id ASC,t1.swipe_date ASC45 GO
最后的效果:
======= 以下代碼減少了CTE虛擬表LEFT JOIN的次數,效率更高。修改于2015-06-24 19:22 ===========
1 ;WITH CTE3 AS ( 2 SELECT 3 card_id 4 ,CONVERT(CHAR(10),swipe_date,23) AS swipe_date 5 ,CONVERT(CHAR(5),swipe_date,108) AS swipe_time 6 FROM CARD_RECORD 7 ) 8 9 ,CTE4 AS (10 SELECT 11 ROW_NUMBER() OVER (PARTITION BY card_id,swipe_date ORDER BY card_id ASC,swipe_date ASC,swipe_time ASC) AS row_no12 ,card_id13 ,swipe_date14 ,swipe_time15 FROM CTE316 )17 18 SELECT 19 card_id20 ,swipe_date21 ,MAX(CASE WHEN row_no = 1 THEN swipe_time ELSE '' END) AS time122 ,MAX(CASE WHEN row_no = 2 THEN swipe_time ELSE '' END) AS time223 ,MAX(CASE WHEN row_no = 3 THEN swipe_time ELSE '' END) AS time324 ,MAX(CASE WHEN row_no = 4 THEN swipe_time ELSE '' END) AS time425 ,MAX(CASE WHEN row_no = 5 THEN swipe_time ELSE '' END) AS time526 ,MAX(CASE WHEN row_no = 6 THEN swipe_time ELSE '' END) AS time627 ,MAX(CASE WHEN row_no = 7 THEN swipe_time ELSE '' END) AS time728 ,MAX(CASE WHEN row_no = 8 THEN swipe_time ELSE '' END) AS time829 ,MAX(CASE WHEN row_no = 9 THEN swipe_time ELSE '' END) AS time930 ,MAX(CASE WHEN row_no = 10 THEN swipe_time ELSE '' END) AS time1031 32 FROM CTE433 GROUP BY card_id,swipe_date34 ORDER BY card_id ASC,swipe_date ASC35 36 GO
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