如果網頁速度過慢或者其他原因，用戶多次提交能導致數據的修改，怎么解決這個問題呢？
這段是放在 Page_Load 中

復制代碼 代碼如下:

if(!Page.IsPostBack)
{
System.Text.StringBuilder s = new System.Text.StringBuilder();
s.Append("a();");
s.Append(this.GetPostBackEventReference(this.Button1));
this.Button1.Attributes.Add("onclick",s.ToString());
}
a() 是 JS
function a()
{
var ok=document.getElementById('Button1');
ok.disabled = true;
return true;
}

復制代碼 代碼如下:

btnSave.Attributes.Add("onclick","this.disabled='true';"+GetPostBackEventReference(btnSave));

復制代碼 代碼如下:

System.Text.StringBuilder s = new System.Text.StringBuilder(); s.Append("var ok=document.getElementById('Button1'); ");
s.Append("ok.disabled = true; ");
s.Append(this.GetPostBackEventReference(this.Button1));
this.Button1.Attributes.Add("onclick",s.ToString());
//.net 2.0以上
Button1.Attributes.Add("onclick", "this.disabled=true;" + this.ClientScript.GetPostBackEventReference(Button1, ""));

復制代碼 代碼如下:

<asp:Button runat="server" UseSubmitBehavior="false" OnClientClick="this.value='Sumbit';this.disabled=true; " Text="Sumbit" />

復制代碼 代碼如下:

protected void Page_Load(object sender, EventArgs e)
{
btn.Attributes.Add("onclick", "state=true;");
StringBuilder sb = new StringBuilder();
sb.Append("if (!state) return;");
sb.Append("var button=document.getElementByIdx_x('btn');");
sb.Append("button.value='Please Wait...';");
sb.Append("document.body.style.cursor='wait';");
sb.Append("button.disabled=true;");
string strScript = "<script>";
strScript = strScript + "var state=false;";
//將函數綁定到頁面的onbeforeunload事件:
strScript = strScript + "window.attachEvent('onbeforeunload',function(){" + sb.ToString() + "});";
strScript = strScript + "</" + "script>";
Page.RegisterStartupScript("onbeforeunload", strScript);
}
protected void Submit_Click(object sender, EventArgs e)
{
//模擬長時間的按鈕處理
System.Threading.Thread.Sleep(2000);
Response.Write("<script>alert('bbbbbb!!');" + "</" + "script>");
}
<asp:Button Text="Submit"
runat="server"/>

復制代碼 代碼如下:

<asp:button runat="server" OnClientClick="this.disabled=true;this.form.submit();" UseSubmitBehavior="False"/>

復制代碼 代碼如下:

this.btnSubmit.Attributes["onclick"]=this.GetPostBackEventReference(this.btnSubmit)+";this.disabled=true;";//防止重復提交