@echo off
:: 保留空行替換字符串
:: 當行首有冒號時會拋掉最開始的幾個連續(xù)冒號(這個問題可以解決)
:: 會忽略以分號開頭的行
:: 不能正確處理感嘆號(因為啟用了變量延遲)
::
::

set file=
set /p file= 請把要處理的文件拉到本窗口：
set "file=%file:"=%"
for %%i in ("%file%") do set "file=%%~fi"
echo.
set replaced=
set /p replaced= 請輸入即將被替換的內容：
echo.
set all=
set /p all= 請輸入替換字符串：
cd.>"%file%_tmp.txt"
setlocal enabledelayedexpansion
for /f "tokens=1* delims=:" %%i in ('findstr /n .* "%file%"') do (
set str=%%j
if not "!str!"=="" set "str=!str:%replaced%=%all%!"
>>"%file%_tmp.txt" echo.!str!
)
copy "%file%" "%file%_bak.txt" >nul 2>nul
move "%file%_tmp.txt" "%file%"
start "" "%file%"