桶排序介紹
桶排序(Bucket Sort)的原理很簡單,它是將數組分到有限數量的桶子里。
假設待排序的數組a中共有N個整數,并且已知數組a中數據的范圍[0, MAX)。在桶排序時,創建容量為MAX的桶數組r,并將桶數組元素都初始化為0;將容量為MAX的桶數組中的每一個單元都看作一個"桶"。
在排序時,逐個遍歷數組a,將數組a的值,作為"桶數組r"的下標。當a中數據被讀取時,就將桶的值加1。例如,讀取到數組a[3]=5,則將r[5]的值+1。
C++實現算法
假設數據分布在[0,100)之間,每個桶內部用鏈表表示,在數據入桶的同時插入排序。然后把各個桶中的數據合并。
#include<iterator>#include<iostream>#include<vector>using namespace std;const int BUCKET_NUM = 10;struct ListNode{ explicit ListNode(int i=0):mData(i),mNext(NULL){} ListNode* mNext; int mData;};ListNode* insert(ListNode* head,int val){ ListNode dummyNode; ListNode *newNode = new ListNode(val); ListNode *pre,*curr; dummyNode.mNext = head; pre = &dummyNode; curr = head; while(NULL!=curr && curr->mData<=val){ pre = curr; curr = curr->mNext; } newNode->mNext = curr; pre->mNext = newNode; return dummyNode.mNext;}ListNode* Merge(ListNode *head1,ListNode *head2){ ListNode dummyNode; ListNode *dummy = &dummyNode; while(NULL!=head1 && NULL!=head2){ if(head1->mData <= head2->mData){ dummy->mNext = head1; head1 = head1->mNext; }else{ dummy->mNext = head2; head2 = head2->mNext; } dummy = dummy->mNext; } if(NULL!=head1) dummy->mNext = head1; if(NULL!=head2) dummy->mNext = head2; return dummyNode.mNext;}void BucketSort(int n,int arr[]){ vector<ListNode*> buckets(BUCKET_NUM,(ListNode*)(0)); for(int i=0;i<n;++i){ int index = arr[i]/BUCKET_NUM; ListNode *head = buckets.at(index); buckets.at(index) = insert(head,arr[i]); } ListNode *head = buckets.at(0); for(int i=1;i<BUCKET_NUM;++i){ head = Merge(head,buckets.at(i)); } for(int i=0;i<n;++i){ arr[i] = head->mData; head = head->mNext; }}
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