C語言實現矩陣翻轉 上下翻轉與左右翻轉
實例代碼：
#include <stdio.h> void matrix (int m, int n, int t) { int arr[m][n]; int i, j, k; for (i = 0; i < m; i++){ for (j = 0; j < n; j++){ scanf("%d", &arr[i][j]); } } if (t == 0){//左右翻轉 for (i = 0; i < m; i++){ for (j = n-1; j >= 0; j--){ if ( j == 0 ) { printf("%d", arr[i][j]); } else { printf("%d ", arr[i][j]); } } printf("/n"); } } else if (t == 1){//上下翻轉 for (i = m-1; i >= 0; i--){ for (j = 0; j < n; j++){ if ( j == n - 1 ) { printf("%d", arr[i][j]); } else { printf("%d ", arr[i][j]); } } printf("/n"); } } } int main() { int m, n, t; scanf("%d %d %d", &m, &n, &t); matrix (m, n, t); return 0; } 動態分配內存
void matrix (int m, int n, int t) { int i, j; int **arr=(int**)malloc(m*sizeof(int*)); for(i = 0; i < m; i++) { arr[i] = (int*)malloc(n * sizeof(int)); for(j = 0; j < n;j++) { scanf("%d", &arr[i][j]); } } /* int **arr = new int*[m]; for(i=0;i<m;i++) { arr[i] = new int[n]; for(j=0;j<n;j++) { scanf("%d", &arr[i][j]); } } */ if (t == 0){//左右翻轉 for (i = 0; i < m; i++){ for (j = n-1; j >= 0; j--){ if ( j == 0 ) { printf("%d", arr[i][j]); } else { printf("%d ", arr[i][j]); } } printf("/n"); } } else if (t == 1){//上下翻轉 for (i = m-1; i >= 0; i--){ for (j = 0; j < n; j++){ if ( j == n - 1 ) { printf("%d", arr[i][j]); } else { printf("%d ", arr[i][j]); } } printf("/n"); } } } 感謝閱讀，希望能幫助到大家，謝謝大家對本站的支持！
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