基于C#實現窗體的抖動是件很有意思的事情，原理并不難，其實是生成隨機數，然后改變Form的左上角的坐標即可。
這里用的是循環來實現的，其實還可以用timer來控制.
我把抖動分成了兩種抖動:
1.生成隨機數，改變窗體左上角坐標，然后立即把窗體的坐上角坐標還原，繼續循環。
2.生成隨機數，改變窗體左上角坐標，循環完畢之后，然后立即把窗體的坐上角坐標還原。
主要功能代碼如下：
//第一種抖動private void button1_Click(object sender, EventArgs e){ int recordx = this.Left; //保存原來窗體的左上角的x坐標 int recordy = this.Top; //保存原來窗體的左上角的y坐標 Random random = new Random(); for (int i = 0; i < 100; i++) { int x = random.Next(rand); int y = random.Next(rand); if (x % 2 == 0) { this.Left = this.Left + x; } else { this.Left = this.Left - x; } if (y % 2 == 0) { this.Top = this.Top + y; } else { this.Top = this.Top - y; } this.Left = recordx; //還原原始窗體的左上角的x坐標 this.Top = recordy; //還原原始窗體的左上角的y坐標 } }//第二種抖動private void button2_Click(object sender, EventArgs e){ int recordx = this.Left; int recordy = this.Top; Random random = new Random(); for (int i = 0; i < 50; i++) { int x = random.Next(rand); int y = random.Next(rand); if (x % 2 == 0) { this.Left = this.Left + x; } else { this.Left = this.Left - x; } if (y % 2 == 0) { this.Top = this.Top + y; } else { this.Top = this.Top - y; } System.Threading.Thread.Sleep(1); } this.Left = recordx; this.Top = recordy;}新聞熱點
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