本文實例講述了C#結合JavaScript實現秒殺倒計時的方法。分享給大家供大家參考。具體如下:
最近做個秒殺活動,要用到倒計時。要求每周三上午10:00開始倒計時
private string Dtime() { byte tempB = (byte)DateTime.Now.DayOfWeek; byte dayByte = (byte)DayOfWeek.Wednesday; DateTime wednesdayNow = DateTime.Now.AddDays(dayByte - tempB); //本星期三 DateTime returnTime = new DateTime (); if (DateTime.Now.DayOfWeek < wednesdayNow.DayOfWeek) { //當前星期小于本星期三 獲取本周星期三 returnTime = new DateTime(wednesdayNow.Year,wednesdayNow.Month,wednesdayNow.Day,10,0,0); } else { //當前星期大于本星期三 獲取下周星期三 DateTime nextWednesday = wednesdayNow.AddDays(7);//下周三 returnTime = new DateTime(nextWednesday.Year,nextWednesday.Month,nextWednesday.Day,10,0,0); } return returnTime.ToString() }
這個方法可以得到每周三的時間,然后用js對該時間進行倒計時
$(document).ready(function() { $('body').everyTime('1s', function() { var nowDate = new Date(); var endDate = new Date($("#sp_next").html().replace(//-/g, "http://")); //這個時間是上個方法返回的時間 var timeold = endDate.getTime() - nowDate.getTime(); var sectimeold = timeold / 1000 var secondsold = Math.floor(sectimeold); var msPerDay = 24 * 60 * 60 * 1000 var e_daysold = timeold / msPerDay var daysold = Math.floor(e_daysold); var e_hrsold = (e_daysold - daysold) * 24 + (daysold * 24); var hrsold = Math.floor(e_hrsold); var e_minsold = (e_hrsold - hrsold) * 60; var minsold = Math.floor((e_hrsold - hrsold) * 60); var seconds = Math.floor((e_minsold - minsold) * 60); if (hrsold > 0 && hrsold < 10) { hrsold = "0" + hrsold; } if (minsold < 10) { minsold = "0" + minsold; } if (seconds < 10) { seconds = "0" + seconds; } if (hrsold < 0) { $(".seckill_time").html("0"); $(".seckill_minute").html("0"); $(".seckill_second").html("0"); } else { $(".seckill_time").html("").html(hrsold); $(".seckill_minute").html("").html(minsold); $(".seckill_second").html("").html(seconds); } });});
希望本文所述對大家的C#程序設計有所幫助。
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