本文實例講述了JS實現的字符串數組去重功能。分享給大家供大家參考，具體如下：
這里只考慮最簡單字符串的數組去重，暫不考慮，對象，函數，NaN等情況，這種用正則實現起來就吃力不討好了。
非正則實現：ES6實現
<script>let str_arr=["b","c",1,"a", 3,"v", "2","e", "6","g", "9", "arr",9, "hello",",6", "9", "1", 2, 6, "b", "c"]function unique(arr){ return [...new Set(arr)]}console.log(unique(str_arr)) </script>運行結果：
ES5實現
<script>var str_arr = ["b","c",1,"a", 3,"v", "2","e", "6","g", "9", "arr",9, "hello",",6", "9", "1", 2, 6, "b", "c"] function unique(arr) { return arr.filter(function(ele, index, array) { return array.indexOf(ele) === index }) } console.log(unique(str_arr))</script>運行結果同上
ES3實現
<script>var str_arr = ["b","c",1,"a", 3,"v", "2","e", "6","g", "9", "arr",9, "hello",",6", "9", "1", 2, 6, "b", "c"]function unique(arr) { var obj = {}, array = [] for (var i = 0, len = arr.length; i < len; i++) { var key = arr[i] + typeof arr[i] if (!obj[key]) { obj[key] = true array.push(arr[i]) } } return array}console.log(unique(str_arr))</script>運行結果同上
用正則實現
<script> var str_arr = ["b","c",1,"a", 3,"v", "2","e", "6","g", "9", "arr",9, "hello",",6", "9", "1", 2, 6, "b", "c"] function unique(arr) { return arr.sort().join(",,"). replace(/(,|^)([^,]+)(,,/2)+(,|$)/g, "$1$2$4"). replace(/,,+/g, ","). replace(/,$/, ""). split(",") } console.log(unique(str_arr))</script>
希望本文所述對大家JavaScript程序設計有所幫助。
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