上次還是CSDN里的朋友回答的，我復(fù)制了下來(lái)。原文如下
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利用統(tǒng)計(jì)文章字?jǐn)?shù)，然后達(dá)到一定字?jǐn)?shù)就截?cái)噍敵?，但是分?yè)的內(nèi)容就會(huì)在莫名其妙的地方截?cái)啵皇呛苡押谩?nbsp;
很簡(jiǎn)單，在要截?cái)嗟牡胤礁浇蚁旅娴姆?hào):
；'”？。！;'".!
如果后面存在<p>或<br>就分頁(yè)。主要是要研究文章的格式。
<%
if Request.ServerVariables("Content_Length") > 0 then
content = Request.Form("textarea1")PageLength = 1000 '每頁(yè)字?jǐn)?shù)
CLength = Len(content)
PageCount = Int(Clength/PageLength) + 1 '計(jì)算頁(yè)數(shù)dim PageArray
redim PageArray(PageCount)Seperator = Array(chr(13),chr(10),"。","！","？","；","，","”","'") '分隔符PageArray(0) = 0
Pos = 0
for j=0 to ubound(Seperator)
Pos = instr(PageArray(i)+900,content,Seperator(j)) 'PageArray(i)+900 附近位置是100字，1-999可調(diào)
while Pos > 0 and Pos < (i+1)*PageLength and Pos > i*PageLength
PageArray(i) = Pos
Pos = instr(Pos+PageLength,content,Seperator(j))
wendif PageArray(i) > 0 then
Response.Write "0:i¦ "&PageArray(i)&"<br>"&j&":j"&Seperator(j)&"<br>"
j = j + ubound(Seperator) + 1
end if
nextfor i=1 to PageCount-1
PageArray(i) = 0
Pos = 0
for j=0 to ubound(Seperator)
Pos = instr(PageArray(i-1)+950,content,Seperator(j))
while Pos > 0 and Pos < (i+1)*PageLength and Pos > i*PageLength
PageArray(i) = Pos
Pos = instr(Pos+PageLength,content,Seperator(j))
wend
if PageArray(i) > 0 then
Response.Write i&":i¦ "&PageArray(i)&"<br>"&j&":j"&Seperator(j)&"<br>"
j = j + ubound(Seperator) + 1
end if
next
nextoutput = mid(content,1,PageArray(0))
output = replace(output,chr(13),"<br>")
Response.Write "<br><br>第1段<br>"
Response.Write outputfor i=1 to PageCount-2
output = mid(content,PageArray(i-1)+1,PageArray(i)-PageArray(i-1))
output = replace(output,chr(13),"<br>")
Response.Write "<br><br>第"&i+1&"段<br>"
Response.Write output
next'最后一段的輸出就沒(méi)寫(xiě)了else
%>
<FORM action="" method=POST id=form1 name=form1>
<TEXTAREA rows=70 cols=120 id=textarea1 name=textarea1>
</TEXTAREA>
<INPUT type="submit" value="Submit" id=submit1 name=submit1>
</FORM>
<%end if%>
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定義有 每頁(yè)面長(zhǎng)度 MaxLength
文本總長(zhǎng)度 TotalLength
掃描文章中每一個(gè)段尾處的硬回車
并計(jì)算該處長(zhǎng)度
一旦超過(guò) MaxLength 則分成第一頁(yè)
刪除此硬回車前的部分 重復(fù)上述操作。
