生成的密碼和用戶輸入可以接受重復(fù)數(shù)字。
所以相對一般規(guī)則的猜數(shù)字可能難度要大不少。
本版本規(guī)則：
A--數(shù)字對，位置也對
B--排除A的結(jié)果后，數(shù)字對，但位置不對
開始后，系統(tǒng)化初始化一個(gè)4位可重復(fù)數(shù)字，如“1223”。假設(shè)用戶第一次輸入“1234”，那么系統(tǒng)將提示“2A1B”，前兩位數(shù)字“12”相同并且位置也相同，為“2A”。后兩位數(shù)字中，用戶輸入的“3”與密文中“3”相同，但兩者位置不同，則為“1B”，最終結(jié)果為“2A1B”。
再假設(shè)用戶此時(shí)輸入“1232”，那么結(jié)果則為“2A2B”，計(jì)算方法與前次一樣。
代碼如下：
#!/bin/bashclearechoecho "###################################################################"echo "# this is a bash-shell game write by Email:breeze7086@gmail.com #"echo "# the game called *digits*,and this version have repeated numbers #"echo "# version 1.0 #"echo "###################################################################"echo -e "/n/n"declare INPUTdeclare PASSWORDdeclare Adeclare Bdeclare Xdeclare Ydeclare LOOP#This funtion init the variable PASSWORD that user need to guessinit_password(){ PASSWORD=`echo $(($RANDOM%10000))` echo $PASSWORD | grep '^[0-9]/{4/}$' >/dev/null 2>&1 if [ $? != 0 ] then init_password else input fi}#This funtion accept the input from user's keyboardinput(){ echo -n "please input a number between 0000-9999:" read INPUT echo $INPUT | grep '^[0-9]/{4/}$' >/dev/null 2>&1 if [ $? != 0 ] then echo "retry a number between 0000-9999 and do not input a char" input else judge fi}#This funtion is the main funtionjudge(){ X=$INPUT Y=$PASSWORD while [ $INPUT != $PASSWORD ] do A=0 B=0 judge_a judge_b LOOP=`expr $LOOP + 1` echo "****************************" echo "* "$A"A"$B"B *" echo "****************************" input done}#This funtion count the variable A's valuejudge_a(){ for i in `seq 4` do VAR_INPUT=`expr substr "$X" $i 1` for j in `seq 4` do VAR_PASSWORD=`expr substr "$Y" $j 1` if [[ $VAR_INPUT = $VAR_PASSWORD && $VAR_INPUT != "" && $VAR_PASSWORD != "" && $i = $j ]] then A=`expr $A + 1` X=`expr substr $X 1 "$[$i-1]"``expr substr $X "$[$i+1]" 4` Y=`expr substr $Y 1 "$[$i-1]"``expr substr $Y "$[$i+1]" 4` judge_a fi done done}#This funtion count the variable B's valuejudge_b(){ for i in `seq 4` do VAR_INPUT=`expr substr "$X" $i 1` for j in `seq 4` do VAR_PASSWORD=`expr substr "$Y" $j 1` if [[ $VAR_INPUT = $VAR_PASSWORD && $VAR_INPUT != "" && $VAR_PASSWORD != "" ]] then B=`expr $B + 1` X=`expr substr "$X" 1 "$[$i-1]"``expr substr "$X" "$[$i+1]" 4` Y=`expr substr "$Y" 1 "$[$j-1]"``expr substr "$Y" "$[$j+1]" 4` judge_b fi done done}#This is the begin of scriptLOOP=1init_passwordecho "#############################################"echo "#congratulations!You have tried $LOOP times! #"echo "# The password is $PASSWORD ! #"echo "#############################################"新聞熱點(diǎn)
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