php實現用于驗證所有類型的信用卡類

2020-03-22 18:12:03

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本文實例講述了php實現用于驗證所有類型的信用卡類。分享給大家供大家參考。具體如下：這個php類比較完整，可以用于驗證各種不同的信用卡，針對信用卡的卡號的通用規則進行了驗證，同時對不同類型的信用卡進行了針對性的識別。
代碼接受一個信用卡號碼和有效日期，如果兩者都有效，則返回TRUE,否則返回FALSE。本插件接受以下參數：
$number 表示信用卡號碼的一個字符串
$expiry 信用卡有效日期，采用07/12或0712這樣的格式// Plug-in 32: Validate Credit Card// This is an executable example with additional code supplied// To obtain just the plug-ins please click on the Download link$card = "4567 1234 5678 9101";$exp = "06/11";echo "Validating: $card : $exp br $result = PIPHP_ValidateCC($card, $exp);if ($result != FALSE) echo "Card Validated";else echo "Card did not validate";function PIPHP_ValidateCC($number, $expiry) // Plug-in 32: Validate Credit Card // This plug-in accepts a credit card number and // an expiry date and returns TRUE or FALSE, // depending on whether the details pass date // and checksum validation. The arguments required // are: // $number: Credit Card Number // $expiry: Expiry date in the form: // 07/12 or 0712 (for July, 2012) $number = preg_replace('/[^/d]/', '', $number); $expiry = preg_replace('/[^/d]/', '', $expiry); $left = substr($number, 0, 4); $cclen = strlen($number); $chksum = 0; // Diners Club if (($left = 3000) && ($left = 3059) || ($left = 3600) && ($left = 3699) || ($left = 3800) && ($left = 3889)) if ($cclen != 14) return FALSE; // JCB if (($left = 3088) && ($left = 3094) || ($left = 3096) && ($left = 3102) || ($left = 3112) && ($left = 3120) || ($left = 3158) && ($left = 3159) || ($left = 3337) && ($left = 3349) || ($left = 3528) && ($left = 3589)) if ($cclen != 16) return FALSE; // American Express elseif (($left = 3400) && ($left = 3499) || ($left = 3700) && ($left = 3799)) if ($cclen != 15) return FALSE; // Carte Blanche elseif (($left = 3890) && ($left = 3899)) if ($cclen != 14) return FALSE; // Visa elseif (($left = 4000) && ($left = 4999)) if ($cclen != 13 && $cclen != 16) return FALSE; // MasterCard elseif (($left = 5100) && ($left = 5599)) if ($cclen != 16) return FALSE; // Australian BankCard elseif ($left == 5610) if ($cclen != 16) return FALSE; // Discover elseif ($left == 6011) if ($cclen != 16) return FALSE; // Unknown else return FALSE; for ($j = 1 - ($cclen % 2); $j $cclen; $j += 2) $chksum += substr($number, $j, 1); for ($j = $cclen % 2; $j $cclen; $j += 2) $d = substr($number, $j, 1) * 2; $chksum += $d 10 $d : $d - 9; if ($chksum % 10 != 0) return FALSE; if (mktime(0, 0, 0, substr($expiry, 0, 2), date("t"), substr($expiry, 2, 2)) time()) return FALSE; return TRUE; 希望本文所述對大家的php程序設計有所幫助。PHP教程

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