python實現簡單http服務器功能

2020-02-15 22:59:31

字體：大中小

來源：轉載

供稿：網友

背景

寫一個python腳本，實現簡單的http服務器功能：

1.瀏覽器中輸入網站地址：172.20.52.163:20014

2.server接到瀏覽器的請求后，讀取本地的index.html文件的內容，回發給瀏覽器

代碼實現

server.py

#!/usr/bin/pythonimport socketimport signalimport errnofrom time import sleep   def HttpResponse(header,whtml): f = file(whtml) contxtlist = f.readlines() context = ''.join(contxtlist) response = "%s %d/n/n%s/n/n" % (header,len(context),context) return response def sigIntHander(signo,frame): print 'get signo# ',signo global runflag runflag = False global lisfd lisfd.shutdown(socket.SHUT_RD) strHost = "172.20.52.163"HOST = strHost #socket.inet_pton(socket.AF_INET,strHost)PORT = 20014 httpheader = '''/HTTP/1.1 200 OKContext-Type: text/htmlServer: Python-slp version 1.0Context-Length: ''' lisfd = socket.socket(socket.AF_INET,socket.SOCK_STREAM)lisfd.bind((HOST, PORT))lisfd.listen(2) signal.signal(signal.SIGINT,sigIntHander) runflag = Truewhile runflag: try:  confd,addr = lisfd.accept() except socket.error as e:  if e.errno == errno.EINTR:   print 'get a except EINTR'  else:   raise  continue  if runflag == False:  break;  print "connect by ",addr data = confd.recv(1024) if not data:  break print data confd.send(HttpResponse(httpheader,'index.html')) confd.close()else: print 'runflag#',runflag print 'Done'

index.html

<html> <head> <title>Python Server</title> </head> <body> <h1>Hello python</h1> <p>Welcom to the python world</br> </body></html>

測試

測試結果：

root@cloud2:~/slp/pythonLearning/socket# ./server_v1.py
connect by ('172.20.52.110', 6096)
GET / HTTP/1.1
Host: 172.20.52.163:20014
Connection: keep-alive
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,*/*;q=0.8
User-Agent: Mozilla/5.0 (Windows NT 5.1) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/33.0.1750.154 Safari/537.36
Accept-Encoding: gzip,deflate,sdch
Accept-Language: zh-CN,zh;q=0.8,en;q=0.6

瀏覽器