本文實例為大家分享了python實現人民幣轉大寫人民幣的具體代碼，供大家參考，具體內容如下

直接上代碼：

# -*- coding: utf-8 -*-def changenum( change_number ): format_num = ["零","壹","貳","叁","肆","伍","陸","柒","捌","玖"] format_name = ["分", "角", "元",    "拾","百","千","萬",    "拾","百","千","億",    "拾","百","千","萬",    "拾","百","千","兆"] if type( change_number ) == str:  if '.' in change_number:   try: change_number = float( change_number )   except: raise ValueError, '%s can/'t change'%change_number  else:   try: change_number = int( change_number )   except: raise ValueError, '%s can/'t change'%change_number if type( change_number ) == float:  real_numbers = []  for i in range( len( format_name ) - 3, -3, -1 ):   if change_number >= 10 ** i or i < 1:    real_numbers.append( int( round( change_number/( 10**i ), 2)%10 ) ) elif isinstance( change_number, (int, long) ):  real_numbers = [ int( i ) for i in str( change_number ) + '00' ] else:  raise ValueError, '%s can/'t change'%change_number zflag = 0       start = len(real_numbers) - 3 change_words = [] for i in range(start, -3, -1):   if 0 <> real_numbers[start-i] or len(change_words) == 0:   if zflag:    change_words.append(format_num[0])    zflag = 0   change_words.append( format_num[ real_numbers[ start - i ] ] )   change_words.append(format_name [i+2])  elif 0 == i or (0 == i%4 and zflag < 3):    change_words.append(format_name [i+2])   zflag = 0  else:   zflag += 1 if change_words[-1] not in (format_name[0], format_name[1]):  change_words.append("整") return ''.join(change_words)#測試# print changenum(865324.98)#查看輸出的結果是否正確

以上就是本文的全部內容，希望對大家的學習有所幫助，也希望大家多多支持武林站長站。