class Point {
    double x;
    double y;

    public Point() {
        this.x = 0;
        this.y = 0;
    }
}
class Line {
    Point a;
    Point b;

    public Line() {
        this.a = new Point();
        this.b = new Point();
    }
    //求兩直線的交點，斜率相同的話res=u.a
    Point intersection(Line u,Line v){
        Point res = u.a;
        double t = ((u.a.x-v.a.x)*(v.b.y-v.a.y)-(u.a.y-v.a.y)*(v.b.x-v.a.x))
            /((u.a.x-u.b.x)*(v.b.y-v.a.y)-(u.a.y-u.b.y)*(v.b.x-v.a.x));
        res.x += (u.b.x-u.a.x)*t;
        res.y += (u.b.y-u.a.y)*t;
        return res;
    }