這是我之前網上看到的,很牛逼的一位大神寫的,一直膜拜中
<!doctype html><html><head></head><body><div id="box" style="width:252px;font:25px/25px 宋體;background:#000;color:#9f9;border:#999 20px ridge;text-shadow:2px 3px 1px #0f0;"></div><script>var map=eval("["+Array(23).join("0x801,")+"0xfff]");var tatris=[[0x6600],[0x2222,0xf00],[0xc600,0x2640],[0x6c00,0x4620],[0x4460,0x2e0,0x6220,0x740],[0x2260,0xe20,0x6440,0x4700],[0x2620,0x720,0x2320,0x2700]];var keycom={"38":"rotate(1)","40":"down()","37":"move(2,1)","39":"move(0.5,-1)"};var dia, pos, bak, run;function start(){ dia=tatris[~~(Math.random()*7)]; bak=pos={fk:[],y:0,x:4,s:~~(Math.random()*4)}; rotate(0);}function over(){ document.onkeydown=null; clearInterval(run); alert("GAME OVER");}function update(t){ bak={fk:pos.fk.slice(0),y:pos.y,x:pos.x,s:pos.s}; if(t) return; for(var i=0,a2=""; i<22; i++) a2+=map[i].toString(2).slice(1,-1)+"<br/>"; for(var i=0,n; i<4; i++) if(/([^0]+)/.test(bak.fk[i].toString(2).replace(/1/g,"/u25a1"))) a2=a2.substr(0,n=(bak.y+i+1)*15-RegExp.$_.length-4)+RegExp.$1+a2.slice(n+RegExp.$1.length); document.getElementById("box").innerHTML=a2.replace(/1/g,"/u25a0").replace(/0/g,"/u3000");}function is(){ for(var i=0; i<4; i++) if((pos.fk[i]&map[pos.y+i])!=0) return pos=bak;}function rotate(r){ var f=dia[pos.s=(pos.s+r)%dia.length]; for(var i=0; i<4; i++) pos.fk[i]=(f>>(12-i*4)&15)<<pos.x; update(is());}function down(){ ++pos.y; if(is()){ for(var i=0; i<4 && pos.y+i<22; i++) if((map[pos.y+i]|=pos.fk[i])==0xfff) map.splice(pos.y+i,1), map.unshift(0x801); if(map[1]!=0x801) return over(); start(); } update();}function move(t,k){ pos.x+=k; for(var i=0; i<4; i++) pos.fk[i]*=t; update(is());}document.onkeydown=function(e){ eval(keycom[(e?e:event).keyCode]);};start();run=setInterval("down()",400);</script></body></html>以上所述就是本文的全部內容，希望大家能夠喜歡。
新聞熱點
疑難解答
