1. 原題： https://www.patest.cn/contests/pat-a-PRactise/1058

2. 思路：

3. 源碼（已AC）：

#include<iostream>using namespace std;int main(void){	//freopen("in.txt", "r", stdin);	int g1, s1, k1;	int g2, s2, k2;	scanf("%d.%d.%d %d.%d.%d", &g1, &s1, &k1, &g2, &s2, &k2);	int g3, s3, k3;	k3 = (k2 + k1) % 29;	s3 = (s2 + s1 + (k2 + k1) / 29) % 17;	g3 = g1 + g2 + (s2 + s1 + (k2 + k1) / 29) / 17;	printf("%d.%d.%d/n", g3, s3, k3);	return 0;}